算法基础/BFS/DFS

1.200. 岛屿数量
题目描述:
给你一个由 '1'(陆地)和 '0'(水)组成的的二维网格,请你计算网格中岛屿的数量。
岛屿总是被水包围,并且每座岛屿只能由水平方向和/或竖直方向上相邻的陆地连接形成。
此外,你可以假设该网格的四条边均被水包围。
示例:
示例 1:
输入:grid = [
["1","1","1","1","0"],
["1","1","0","1","0"],
["1","1","0","0","0"],
["0","0","0","0","0"]
]
输出:1

示例 2:
输入:grid = [
["1","1","0","0","0"],
["1","1","0","0","0"],
["0","0","1","0","0"],
["0","0","0","1","1"]
]
输出:3

解答描述:
一个非常典型的BFS广度优先搜索,求连通分量。
代码
class Solution {
public:
void BFS(vector

算法基础/BFS/DFS最先出现在Python成神之路

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作者:zhangchen
链接:https://www.techfm.club/p/24608.html
来源:TechFM
文章版权归作者所有,未经允许请勿转载。

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