buu-findit

下载后为一个apk文件 ApkIDE打开 查看main函数,发现两段字符串
a=[0x54,0x68,0x69,0x73,0x49,0x73,0x54,0x68,0x65,0x46,0x6c,0x61,0x67,0x48,0x6f,0x6d,0x65]

b=[0x70,0x76,0x6b,0x71,0x7b,0x6d,0x31,0x36,0x34,0x36,0x37,0x35,0x32,0x36,0x32,0x30,0x33,0x33,0x6c,0x34,0x6d,0x34,0x39,0x6c,0x6e,0x70,0x37,0x70,0x39,0x6d,0x6e,0x6b,0x32,0x38,0x6b,0x37,0x35,0x7d]

s1 = ""
for i in a:
s1 += chr(i)
s2 = ""
for i in b:
s2 += chr(i)
print(s1)
pri

buu-findit最先出现在Python成神之路

版权声明:
作者:Alex
链接:https://www.techfm.club/p/16142.html
来源:TechFM
文章版权归作者所有,未经允许请勿转载。

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